Location Transport

need help in physics?

HRW5 10-3E The National Transportation Safety Board is testing the crashworthiness of a new car. The 1.36 103 kg vehicle, moving at 15.6 m/s, is allowed to collide with a bridge abutment, being brought to rest in a time of 0.465 s. What force, assumed constant, acted on the car during impact? N

Public Comments

1. Sorry, thats a crazy subject. I'm glad I never took it :)!! Good luck though !
2. This problem can be solved in many ways, but they're all based on the second Newton's law: F = ma = m x Δv/Δt = m x v / t = 1360 kg x 15.6 m/s / 0.465 s = = 45.6 kN
3. impulse is changing momentum, when the car is moving, it has momentum, in order to bring the car to stop, impulse has to take away all of the momemtum Ft = mv F(.465) = (1.36x10^3kg)(0 - 15.6) F(.465) = -21216 F = -45,625.8N the negative means the force is opposite of the motion.