HELP WITH PRE ALGRBRA PROBLEM!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! NEED IT BY TODAY!!!!!!!!!!!!!!?
OK MY TEACHER is really strict so try to work things out please and thank you!!!!!!! here's the question A FREIGHT TRAIN with 80 cars transports coal and iron ore. Each car carries either 100 tons of coal or 90 tons of iron ore. question A) Let c represent the number of cars carrying coal. Write and simplify an expression in terms of c for the total weight of the freight transported by the train. B) Suppose 28 of the trains cars carry coal. What is the total weight of all the freight? and the last question simplfy the expression a+(2a)+ (10-3a) THANKS REMEMBER WORK OUT THE PROBLEMS!!!!!!!!!!! MY TEACHER IS REALLY STRICT!!!!!!!!!! :)
Public Comments
- 1) C = 28, that means the other 52 cars carry Iron ore. I = 52 100 C + 90 I = 100(28) + 90 (52) = 2800 + 4680 = 7480 tons. 2) 1a + 2a + 10-3a= 10 (just add all the a's together)
- half the fun of a word problem is getting it into the numbers so let's have fun Train = 80 C = Coal cars C = 100 I = iron ore cars = 90 Train = coal cars + iron ore cars T = C100 + (80-C)(90) B) C = 28 T = C100 + (80-C)(90) substitute T = (28)(100) + (80-28)(90) and you have it from here And the last question simplify the expression a+(2a)+ (10-3a) 3a + 10 - 3a 10 all the best
Powered by Yahoo! Answers